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a5d7b0f4f

Denys Vlasenko
Denys Vlasenko
2021-07-02
SUCCESS Duration: 154s

Subject

awk: fix detection of VAR=VAL arguments

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No binary (build failed)

Architecture & Compiler Flags

Architecture: x86_64-linux-gnu Compiler: gcc (Ubuntu 11.4.0-1ubuntu1~22.04.3) 11.4.0

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Build Log

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Commit Diff GitHub →

editors/awk.c+4 -5
@@ -2679,7 +2679,8 @@ static int is_assignment(const char *expr)
{
char *exprc, *val;
- if (!isalnum_(*expr) || (val = strchr(expr, '=')) == NULL) {
+ val = (char*)endofname(expr);
+ if (val == (char*)expr || *val != '=') {
return FALSE;
}
@@ -2699,7 +2700,6 @@ static rstream *next_input_file(void)
#define rsm (G.next_input_file__rsm)
#define files_happen (G.next_input_file__files_happen)
- FILE *F;
const char *fname, *ind;
if (rsm.F)
@@ -2712,20 +2712,19 @@ static rstream *next_input_file(void)
if (files_happen)
return NULL;
fname = "-";
- F = stdin;
+ rsm.F = stdin;
break;
}
ind = getvar_s(incvar(intvar[ARGIND]));
fname = getvar_s(findvar(iamarray(intvar[ARGV]), ind));
if (fname && *fname && !is_assignment(fname)) {
- F = xfopen_stdin(fname);
+ rsm.F = xfopen_stdin(fname);
break;
}
}
files_happen = TRUE;
setvar_s(intvar[FILENAME], fname);
- rsm.F = F;
return &rsm;
#undef rsm
#undef files_happen